Last Update:  5th March 2017
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Theory of Bidding 3NT or 6NT

Normal text books say for 3NT you need a minimum of 25 HCP's and for 6NT the minimum is 33 HCP's
but what is the absolute theoretical minimum required?


How low can you go??




3NT
  North
♠ -
-
xxxxxx
♣ xxxxxxx

  South bids 3NT with 6 HCP's

West is on lead

West
♠ AKxxxx
AKxxxxx
-
♣ -

  East
♠ -
♥ -
xxxxxx
♣ xxxxxxx

West will get A♠, K♠, Aand K.  After this South will run home the remaining 9 tricks.
  South
♠ QJT9872
♥ QJT987
-
♣ -

  So in theory 3NT can be made with only 6HCP's, all be it a very favourable distribution.

ooOoo


6NT
  North
♠ -
-
xxxxxx
♣ xxxxxxx
  South bids 6NT with 9 HCP's

West is on lead
West
♠ K
KQJT98765432
-
-
  East
♠ Q
-
xxxxxxxxxxxx
♣ -
 
No matter what West leads South can take the A or A♠.  Then south will take 11 more tricks before playing the lone
  South
♠ AJT98765432
A
x
♣ -

  So in theory 6NT can be made with only 9HCP's, all be it a very favourable distribution.




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