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Theory of Bidding 3NT or 6NT
Normal text books say for 3NT you need a minimum of 25 HCP's and for 6NT the minimum is 33 HCP's
but what is the absolute theoretical minimum required?
How low can you go??
3NT
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North
♠ -
♥ -
♦ xxxxxx
♣ xxxxxxx
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South bids 3NT with 6 HCP's
West is on lead
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West
♠ AKxxxx
♥ AKxxxxx
♦ -
♣ -
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East
♠ -
♥ -
♦ xxxxxx
♣ xxxxxxx
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West will get A♠, K♠, A♥ and K♥. After this South will run home the remaining 9 tricks.
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South
♠ QJT9872
♥ QJT987
♦ -
♣ -
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So in theory 3NT can be made with only 6HCP's, all be it a very favourable distribution.
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ooOoo
6NT
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North
♠ -
♥ -
♦ xxxxxx
♣ xxxxxxx |
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South bids 6NT with 9 HCP's
West is on lead |
West
♠ K
♥ KQJT98765432
♦ -
♣ -
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East
♠ Q
♥ -
♦ xxxxxxxxxxxx
♣ - |
No matter what West leads South can take the A♥ or A♠. Then south will take 11 more tricks before playing the lone ♦ |
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South
♠ AJT98765432
♥ A
♦ x
♣ -
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So in theory 6NT can be made with only 9HCP's, all be it a very favourable distribution. |
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